The documentation covers what MATLAB supports.

–Loren

You need to modify your end-of-file check to be at the beginning of your while loop, not at the end.

The error you are getting is because you are passing -1 (end-of-file) to regexp.

-=>J

–Loren

What’s the appropriate, elegant way to get at the numeric value?

I have an ascii text file (notepad) with lines of values with the following format.

first= 320 second= 234566 third= -0.24 …
first= 788 second= 256667 third= -0.24 …
and so on.

I anticipated using code like the following to create a matrix of the numeric values in my text file that match my patterns.

fid = fopen(’accuSUMok.txt’);
i = 1;
while 1
tline = fgetl(fid);
pat = ‘ first=\s+\d+’;
a = regexp(tline,pat,’match’);
disp(a);
pat = ‘\d+’;
c = regexp(a,pat,’match’);
disp(c);
pat = ‘ third=\s+\-0\.\d+’;
b = regexp(tline,pat,’match’);
disp(b);
pat =’\-0\.\d+’;
d = regexp(b,pat,’match’);
disp(d);
j = [ a c b d]
%printf(’%s %s’, a, b, c, d);
if ~ischar(tline), break, end
end
fclose(fid);

But what I see is, many lines of, with the error at end of file.:

‘ first= 325′

{1×1 cell}

‘ third= -0.36′

{1×1 cell}

??? Undefined function or method ‘regexp’ for input arguments of type ‘double’.

Error in ==> reg at 7
a = regexp(tline,pat,’match’);

What can I do to elegantly put the numeric values into an array?
tia

-=>J

My initial thought was that you should use textscan for your problem. Unfortunately, textscan will stop processing if it encounters data that it can not convert, as opposed to the NaNs that you want.

You can get your result using a couple of splits:

Create some sample data:

>> str = sprintf(’123 | 456 | 6.4|asdd\n124 | 457 | 6.8|asdd\n125 | 458 | 7.0|qwerty’)
str =
123 | 456 | 6.4|asdd
124 | 457 | 6.8|asdd
125 | 458 | 7.0|qwerty

Split the data on newlines to find the rows:

>> rows = regexp(str, ‘\n’, ’split’)
rows =
[1×20 char] [1×20 char] [1×22 char]

Now split the rows into individual cells:

>> cells = regexp(rows, ‘\s*\|\s*’, ’split’)
cells =
{1×4 cell} {1×4 cell} {1×4 cell}

Since cells is now a 1×3 cell of 1×4 cells, vertically concatenate them to recreate the original shape of the data:

>> cells = vertcat(cells{:})
cells =
‘123′ ‘456′ ‘6.4′ ‘asdd’
‘124′ ‘457′ ‘6.8′ ‘asdd’
‘125′ ‘458′ ‘7.0′ ‘qwerty’

Now str2double will do the rest of the work:

>> str2double(cells)
ans =
123.0000 456.0000 6.4000 NaN
124.0000 457.0000 6.8000 NaN
125.0000 458.0000 7.0000 NaN

-=>J