You gave me the direction I needed to extract relevant info from the matlab dir filename command. Such as:

function Subdirs = OneLevelSubDirs(directory,match)
% xxx Need Help xxx
% Subdirs = OneLevelSubDirs(directory,match)

if nargin < 2 || isempty(match)
match = '*';
end

X = dir(directory);

Xdir = {X(:).name};
Xdir = Xdir(find(cell2mat({X(:).isdir})));
Subdirs = Xdir(~cellfun(@(x)ismember(x,{'.';'..'}),Xdir));

Did I mention thank you?

When I use the wavread() function and import the data into sptool it say thats an [array] so i couldnt create the spectrum, this tool only work with vectors. So how can i turn this array into vector?

a little help here please

To do this you can use DEAL, but I think Doug’s question is a good one: why do you need/want to do it this way?

% Make sure people2 doesn't exist yet
% This way you can tell that the command performed
% the initial creation correctly
clear people2

% Define the cell array of names
S = {'bob', 'john'};

% DEAL the elements of the cell into the struct
[people2(1:2).name] = deal(S{:})

If you’re using release R14 or later, you can omit the DEAL as described in the Release Notes.

I do not know of a way to do that. You seem to be able to get the data in in other ways, why is it important to do it in this particular manner?

Doug

I have a small question that I’ve not been able to find the solution to online. I’m hoping you may be able to shed some light on the matter.

The following structure has 2 elements.

people = struct(...
'name',{'bob', 'john'},...
'numKids',{0, 2}, ...
'kidsage',{[],[12,9]});

each element people(1), people(2) has three frields (name, numKids, kidsage)

Instead of declaring the structure in one line as above, I would like to define it one field at a time.
The closest working example I’ve been able to come up with is

people = struct

people.('name') = {'bob, 'john'}
people.('numkids') = {0, 2}
people.('kidsage') = {[], [12, 9]}

But defined in this way, the people structure only has one element.
ie.

people(1) =

name: {'bob' 'john'}
numkids: {[0] [2]}
kidsage: {[] [12, 9]}

Any ideas?

weather = repmat(struct('temp', 72, 'rainfall', 0.0),1,3);
nums = [23 10 12];
cellArray = num2cell(nums - [weather(:).temp])
[weather(:).rainfall] = cellArray{:}

Is there no way to assign each element of the result of num2cell to weather.rainfall on a single line.

Shy not just save it? Why are you trying to pull them out of the structure?

Doug

I ran into the same problem described by the previous two posts.

names = {'Peter','Paul','Mary'};
ages = {25,29,26};
[people(1:3).name] = names{:};
[people(1:3).age] = ages{:};

Now

save('test','-struct','people')

yields:
??? Error using ==> save
The argument to -STRUCT must be the name of a scalar structure variable.

whereas

person = people(1);
save('test','-struct','person')

is no problem.

The following would work

save('test','people')

but is very unhandy as

x = load('test');

makes x a 1×1 struct with field people, and would require additionally

x = x.people;

So the question is:
What is the best way to save a struct array?

Emil

by the way, if ages was a 1×3 double [25,29,26] and not a 1×3 cell:
How would I deal it across the struct array people? This is the same problem as adressed by Dan on Aug 4th

I do not understand your question. What have you tried?

Doug