[structArray(1:length(array)).fieldname] = deal(num2cell(array))

ends up assigning the whole array to every instance of fieldname, instead of distributing the array across those instances. What does seem to work is:

cell_array = num2cell(array);
[structArray(1:length(array)).fieldname] = cell_array{:};

I leave it as an exercise for a MATLAB guru to splain why this is the case.

s{1} = s0
s{2} = s1
s{1}.field1
s{1}.field1(1,3)

Doug

s0 = struct('field1', [v1 v2], 'field2', [v3 v4]);
s1 = struct('field1', [v1' v2'], 'field2', [v3' v4']);

I want another data structure s = [s0, s1] so that I can access s0(1) like s(0,1). How can I do that?

[structArray(:).fieldname] = deal(num2cell(array))

Of course, the length of array should be the same as the length of structArray, but if structArray doesn’t exist yet, then you can do:

[structArray(1:length(array)).fieldname] = deal(num2cell(array))

If array is already a cell array, you can avoid using both deal and num2cell (although they will still work) and use:

[structArray(:).fieldname] = array{:}
or
[structArray(1:length(array)).fieldname] = array{:}

An example, modifying the struct array ‘people’ from the video:

names = {’Larry’,'Moe’,'Curly’};
[people(:).name] = names{:};

Yes, you are correct. I can not believe I over looked that. There are so many ways to do certain things in MATLAB.

Doug

To take this one step further, one advantage of Arrays of Structures would be the ability to have vectors of different lengths for each numerical part, and a cell array of names of different lengths for each name part.

For example:

people(1).name=’Erin’
people(2).name={’Joan’ ‘Carla’}
people(1).sim=44
people(2).sim=[561 49]