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	<title>Comments on: Challenge: Metronome and Cart Equations of Motion</title>
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	<link>http://blogs.mathworks.com/seth/2008/10/09/challenge-metronome-and-cart-equations-of-motion/</link>
	<description>This blog is about Simulink.</description>
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		<title>By: Thomas Steffen</title>
		<link>http://blogs.mathworks.com/seth/2008/10/09/challenge-metronome-and-cart-equations-of-motion/#comment-575</link>
		<dc:creator>Thomas Steffen</dc:creator>
		<pubDate>Tue, 14 Oct 2008 18:05:56 +0000</pubDate>
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		<description>I have uploaded a file, but it will take a while to appear. I think the synchronisation will not work with a purely linear model, because that will produce several resonance frequencies. I modelled the driving force of the metronome, and that did the trick.</description>
		<content:encoded><![CDATA[<p>I have uploaded a file, but it will take a while to appear. I think the synchronisation will not work with a purely linear model, because that will produce several resonance frequencies. I modelled the driving force of the metronome, and that did the trick.</p>
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		<title>By: Seth</title>
		<link>http://blogs.mathworks.com/seth/2008/10/09/challenge-metronome-and-cart-equations-of-motion/#comment-572</link>
		<dc:creator>Seth</dc:creator>
		<pubDate>Fri, 10 Oct 2008 19:08:17 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.mathworks.com/seth/2008/10/09/challenge-metronome-and-cart-equations-of-motion/#comment-572</guid>
		<description>@ABindermann - you are right... I should flip the metronome scope.  Is this an appropriate mechanical model for a metronome?  I have played around with a version using an inverted representation and a spring to stabilize it, and I didn&#039;t see much difference in the behavior.  The other experiment I tried was adding friction to the metronome and an energy reserve to kick the pendulum back.  I found all of this made things more complicated without much benefit.

This is the metronome I was thinking about as I approached the problem:

&lt;img src=&quot;http://blogs.mathworks.com/images/seth/2008Q4/metronomePendulum.png&quot;/&gt;</description>
		<content:encoded><![CDATA[<p>@ABindermann &#8211; you are right&#8230; I should flip the metronome scope.  Is this an appropriate mechanical model for a metronome?  I have played around with a version using an inverted representation and a spring to stabilize it, and I didn&#8217;t see much difference in the behavior.  The other experiment I tried was adding friction to the metronome and an energy reserve to kick the pendulum back.  I found all of this made things more complicated without much benefit.</p>
<p>This is the metronome I was thinking about as I approached the problem:</p>
<p><img src="http://blogs.mathworks.com/images/seth/2008Q4/metronomePendulum.png"/></p>
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		<title>By: ABindemann</title>
		<link>http://blogs.mathworks.com/seth/2008/10/09/challenge-metronome-and-cart-equations-of-motion/#comment-571</link>
		<dc:creator>ABindemann</dc:creator>
		<pubDate>Thu, 09 Oct 2008 16:30:44 +0000</pubDate>
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		<description>Hmmm, is a simple pendulum an appropriate mechanical model for a metronome?  What you&#039;ve modeled is a vertically hanging, gravity stabilized pendulum rather than a spring stabilized inverted pendulum.  Based on your approach you should &quot;flipud&quot; your metronome scope ;-)</description>
		<content:encoded><![CDATA[<p>Hmmm, is a simple pendulum an appropriate mechanical model for a metronome?  What you&#8217;ve modeled is a vertically hanging, gravity stabilized pendulum rather than a spring stabilized inverted pendulum.  Based on your approach you should &#8220;flipud&#8221; your metronome scope ;-)</p>
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