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	<title>Comments on: Puzzler: Ultimate Frisbee- call it!</title>
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	<link>http://blogs.mathworks.com/videos/2009/10/27/puzzler-ultimate-frisbee-call-it/</link>
	<description>Doug Hull is a proud MathWorker who is on a mission to help you with MATLAB.</description>
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		<title>By: Oliver Woodford</title>
		<link>http://blogs.mathworks.com/videos/2009/10/27/puzzler-ultimate-frisbee-call-it/#comment-1645</link>
		<dc:creator>Oliver Woodford</dc:creator>
		<pubDate>Wed, 28 Oct 2009 09:34:40 +0000</pubDate>
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		<description>Sorry, Doug. I only just noticed your &quot;email me with solutions&quot; request. I hope I haven&#039;t spoilt it for anyone else.</description>
		<content:encoded><![CDATA[<p>Sorry, Doug. I only just noticed your &#8220;email me with solutions&#8221; request. I hope I haven&#8217;t spoilt it for anyone else.</p>
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	<item>
		<title>By: Oliver Woodford</title>
		<link>http://blogs.mathworks.com/videos/2009/10/27/puzzler-ultimate-frisbee-call-it/#comment-1644</link>
		<dc:creator>Oliver Woodford</dc:creator>
		<pubDate>Wed, 28 Oct 2009 09:31:25 +0000</pubDate>
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		<description>Let p be the probability of &quot;heads&quot;, so (1 - p) is the probability of &quot;tails&quot;. The probability of same is therefore (p^2 + (1-p)^2) and the probability of different is (2*p*(1-p)). We can plot those over p = [0,1]:
&lt;pre&gt;
p = (0:0.001:1)&#039;; plot(p, [p.^2 + (1-p).^2, 2*p.*(1-p)]); legend Same Different
&lt;/pre&gt;
From this you&#039;ll see that the probability of same is always greater than or equal to the probability of different, so it&#039;s the better call to make.</description>
		<content:encoded><![CDATA[<p>Let p be the probability of &#8220;heads&#8221;, so (1 &#8211; p) is the probability of &#8220;tails&#8221;. The probability of same is therefore (p^2 + (1-p)^2) and the probability of different is (2*p*(1-p)). We can plot those over p = [0,1]:</p>
<pre>
p = (0:0.001:1)'; plot(p, [p.^2 + (1-p).^2, 2*p.*(1-p)]); legend Same Different
</pre>
<p>From this you&#8217;ll see that the probability of same is always greater than or equal to the probability of different, so it&#8217;s the better call to make.</p>
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	<item>
		<title>By: Marcial Medina</title>
		<link>http://blogs.mathworks.com/videos/2009/10/27/puzzler-ultimate-frisbee-call-it/#comment-1643</link>
		<dc:creator>Marcial Medina</dc:creator>
		<pubDate>Wed, 28 Oct 2009 01:59:02 +0000</pubDate>
		<guid isPermaLink="false">http://blogs.mathworks.com/videos/2009/10/27/puzzler-ultimate-frisbee-call-it/#comment-1643</guid>
		<description>Is better than I don´t say to much with me happend the same... lol and I love to play too !</description>
		<content:encoded><![CDATA[<p>Is better than I don´t say to much with me happend the same&#8230; lol and I love to play too !</p>
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