Supremum

著者 Cleve Moler, September 24, 2012

30 ビュー (過去 30 日間) | 0 いいね | 0 コメント

Find the supremum of this function.

Favorite Function
Calculus
Sample
Think
Supremum

Favorite Function

Here is one of my favorite functions. What is its maximum?

$$ f(x) = \tan { \sin {x} } - \sin { \tan {x} } $$

Let's plot it with ezplot, which is pronounced easy-plot.

f = @(x) tan(sin(x)) - sin(tan(x))
ezplot(f,[-pi,pi])

f = 

    @(x)tan(sin(x))-sin(tan(x))

The function is very flat at the origin. Its Taylor series begins with $x^7$. It oscillates infinitely often near $\pm \pi/2$. It is linear as it approaches zero again at $\pm \pi$. And, most important for our purposes here, ezplot has picked the limit on the y-axes to be between 2.5 and 3.

syms x
F = sym(f)
disp('taylor = ')
pretty(taylor(F,x,'order',10))
ylim = get(gca,'ylim')

 
F =
 
tan(sin(x)) - sin(tan(x))
 
taylor = 
 
      9    7 
  29 x    x 
  ----- + -- 
   756    30

ylim =

  -2.867712755182179   2.867712755182179

Calculus

We learn in calculus that a maximum occurs at a zero of the derivative. But this function is not differentiable in the vicinity of $\pi/2$. The most interesting thing about an ezplot of the derivative is the title. Trying to find a zero of diff(F) is meaningless.

ezplot(diff(F),[-pi,pi])

Sample

We can sample the function near $\pi/2$ to get a numerical approximation to the value of the maximum. Is that good enough?

x = 3*pi/8 + pi/4*rand(1,1000000);
y = f(x);
format long
smax = max(y)

smax =

   2.557406355782225

Think

The computer has been a help, but we can do this without it.

$$ \sin{x} \le 1 $$

$$ \sin{ \tan {x} } \le 1 $$

and

$$ \tan {\sin{x}} \le \tan {1} $$

Consequently

$$ f(x) \le 1 + \tan {1} $$

Supremum

But I want to be a little more careful. As $x$ approaches $\pi/2$, $\tan{x}$ blows up. So $f(x)$ is actually not defined at $\pi/2$. For the domain of this function, one of the less than or equals changes to just a less than.

$$ \sin{x} < 1 $$

$$ \tan {\sin{x}} < \tan {1} $$

$$ f(x) < 1 + \tan {1} $$

The precise answer to my original question is that this function does not have a maximum. It has a "least upper bound" or supremum, the smallest quantity that the function does not exceed. The sup is:

$$ \sup {f(x)} = 1 + \tan {1} $$

Now we can take a look at the numerical value.