Steve on Image Processing with MATLAB

Image processing concepts, algorithms, and MATLAB


Steve on Image Processing with MATLAB has been archived and will not be updated.

Upslope area – Plateau detection

In my previous upslope area post, I showed this graphic of pixel flow around North Pond in Milford, Massachusetts:

Notice that pixels in the pond have no arrows. In fact, the pixelFlow M-file I showed previously is unable to compute a pixel flow direction or magnitude for these pixels because they are in a flat region, or plateau. More specifically, pixelFlow returns a flow direction of NaN for any pixel that has no downhill neighbor.

There is a simple way to find all such pixels using morphological erosion. Erosion with a flat structuring element is equivalent to a local minimum operator. If the minimum value of a pixel and its neighbors equals the pixel itself, then we'll call it a plateau pixel.

s = load('upslope_sample_dem');
pond = s.Zm(140:280, 160:230);
plateaus = imerode(pond, ones(3,3)) == pond;
imshow(plateaus, 'InitialMagnification', 'fit')

I'd like to classify plateaus into three types:

  • plateaus with downhill but no uphill neighbors; these are called regional maxima
  • plateaus with uphill but no downhill neighbors; these are called regional minima
  • plateaus with both uphill and downhill neighbors

The Image Processing Toolbox has functions that find regional maxima and regional minima:

max_plateaus = imregionalmax(pond);
imshow(max_plateaus, 'InitialMagnification', 'fit')
title('Max plateaus')
min_plateaus = imregionalmin(pond);
imshow(min_plateaus, 'InitialMagnification', 'fit')
title('Min plateaus')

We can now identify pixels in plateaus with both uphill and downhill neighbors by using logical operators:

mid_plateaus = plateaus & ~(max_plateaus | min_plateaus);
imshow(mid_plateaus, 'InitialMagnification', 'fit')
title('Mid plateaus')

Next time I'll work on a procedure for calculating flow directions for these different kinds of plateau pixels.

Published with MATLAB® 7.4

  • print


To leave a comment, please click here to sign in to your MathWorks Account or create a new one.