Today’s challenge is one where you need to figure out if two rectangles have a non-zero area of overlap.
The rectangles will be specified as follows:
Just fill in your part of the code until you get the binary variable overlap defined.
ax = sort(rand(1,2)); ay = sort(rand(1,2)); bx = sort(rand(1,2)); by = sort(rand(1,2)); clf rectangle('position',[ax(1) ay(1) diff(ax) diff(ay)], 'edgecolor', 'r') hold on rectangle('position',[bx(1) by(1) diff(bx) diff(by)], 'edgecolor', 'k') axis equal %your code here overlap = %1 for overlap, 0 for non-overlapping
When you post your code in the comments, please use the tags
<pre> <code> all the code so someone can just copy and paste it from the comments. </code> </pre>
My solution is already posted.
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