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Downsampling polygons

Jiro's pick this week is Polygon simplification by Peter Bone.

Continuing from one of my recent posts on "Connecting points with smooth curves", I came across this new entry by Peter that would work nicely with the hobbysplines function in tracing objects.

Here's how I would use it. Let's start with the original amoeba image.

im = imread('amoeba.png');

I'll convert this grayscale image to black and white, and use a function called bwboundaries from the Image Processing Toolbox to automatically trace out the boundaries.

im2 = im2bw(im);
boundaries = bwboundaries(~im2, 'noholes')
boundaries = 
    [1696x2 double]
    [  30x2 double]
    [  33x2 double]
    [ 111x2 double]
    [  31x2 double]
    [  34x2 double]

Notice that bwboundaries returned a cell array of points for each boundary it found. In this case, it found 6 boundaries. For this discussion, I'll just focus on the largest boundary, i.e. the boundary with the most number of points. I can see that it is the first element. Question for everyone: how would I programmatically find the largest boundary? There are multiple ways of doing it, from basic MATLAB programming to advanced image processing. Post your response below.

largest = boundaries{1};
hold on
hold off

Now, suppose that I don't care for the details (e.g. the individual hairs) and would like to get just the general shape of the amoeba. I can do some filtering or smoothing of the data, or simply down-sample the boundary points. Peter's reduce_poly reduces the points by automatically removing the "least important" points. For example, I can ask for 100 points.

numpts = 100;
largest2 = reduce_poly(largest', numpts)';

hold on
hold off

That's better, but it's still too many points for my taste. I can modify numpts and rerun the block of code. Or, I can increment a value and run the section interactively.

I'll go with numpts = 20 for this case.

numpts = 20;
largest2 = reduce_poly(largest', numpts)';

hold on
hold off

Now, I'll use Will's hobbysplines to connect the points with smooth splines.

% Convert the boundary points to the format required by hobbysplines
pts = fliplr(largest2(1:end-1,:));

hobbysplines(num2cell(pts,2), ...
    'linestyle',{'linewidth',2}, ...


Let us know what you think here or leave a comment for Peter.

Published with MATLAB® R2013b

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