File Exchange Pick of the Week

October 30th, 2009

Bob's pick this week is Allstats by Francisco de Castro.

The file is simple enough. Given a data set,

x = randn(1000,1);
hist(x,100)

allstats returns a list of statistical values.

myStats = allstats(x)

myStats = 
      min: -3.1289
      max: 2.9371
     mean: -0.06815
      std: 1.0019
     mode: -3.1289
     q2p5: -1.9519
       q5: -1.7128
      q25: -0.73464
      q50: -0.072006
      q75: 0.55077
      q95: 1.6351
    q97p5: 1.8844

The mean should be close to zero,

myStats.mean

ans =
     -0.06815

and the standard deviation should be close to one.

myStats.std

ans =
       1.0019

How convenient.

As it turns out, this month the File Exchange recently celebrated a major milestone. Allstats has the honor of being the official 10,000-th submission. Congratulations to Francisco and every contributor who made this possible! Growth of the File Exchange has been absolutely amazing.

If only my retirement account was that impressive! (sigh)

Comments?

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Published with MATLAB® 7.9

14:42 UTC | Posted in Picks | Permalink | 5 Comments »

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5 Responses to “allstats”

1. oleg replied on October 31st, 2009 at 19:08 UTC :
   

   Allstats has no checks, no comments and could also be improved (talking about prctile implementatio). Not to mention that a function which deserves an “all” prefix should at least include skewness and kurtosis.

2. oleg replied on November 5th, 2009 at 14:48 UTC :
   

   The author has implemented skewness, kurtosis and checks answering appropriately to the critic.

3. Jon replied on November 8th, 2009 at 04:36 UTC :
   

   This is a useful tool – but in fairness I have to point out that it is remarkably similar to a routine of the same name published by D. C. Hanselman in Mastering Matlab 7 published in 2005. Hanselman’s routine has the added virtue of implementing all of the statistical measures internally and thus does not require the Statistics Toolbox.

4. bathroom taps replied on November 27th, 2009 at 01:31 UTC :
   

   Cool post I will continue to look out for anymore of your future posts.

5. Bob replied on November 30th, 2009 at 14:17 UTC :
   

   Thanks to everyone for the comments. Special thanks to Francisco for responding to feedback from others to improve his submission. Much appreciated!

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a = magic(3);
sum(a)
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