# Ways to Perform Calculations on Groups of Data in Tables 4

Posted by **Loren Shure**,

Today I'd like to introduce a guest blogger, Stephen Doe, who works for the MATLAB Documentation team here at MathWorks. Stephen will discuss different methods for grouping data, and performing calculations on those groups, using Tables.

### Contents

#### Create Table

Tables are convenient containers for column-oriented data. The variables in a table can have different data types, but must have the same number of rows. You can access table data by row, by variable, or by variable name. And you can specify groups within table variables, to perform calculations on those groups. Today I will show several different ways to apply functions to groups in tables.

First, let's create a table. You can create a table using the `table` function, the Import Tool, or the `readtable` function. I'm going to use `readtable` to read data from a sample file that ships with MATLAB. The file `outages.csv` contains simulated data for electric power outages over a period of 12 years in the United States. Read the table. To display the first five rows, use table indexing.

T = readtable('outages.csv','Format','%C%D%f%f%D%C'); T(1:5,:)

ans = 5×6 table Region OutageTime Loss Customers RestorationTime Cause _________ ________________ ______ __________ ________________ _______________ SouthWest 2002-02-01 12:18 458.98 1.8202e+06 2002-02-07 16:50 winter storm SouthEast 2003-01-23 00:49 530.14 2.1204e+05 NaT winter storm SouthEast 2003-02-07 21:15 289.4 1.4294e+05 2003-02-17 08:14 winter storm West 2004-04-06 05:44 434.81 3.4037e+05 2004-04-06 06:10 equipment fault MidWest 2002-03-16 06:18 186.44 2.1275e+05 2002-03-18 23:23 severe storm

There are six columns in the file. Since I want to specify the data types of the table variables, I use the `Format` name-value pair argument. `T` has two categorical variables (specified with `%C`), two datetime variables (`%D`) and two numeric variables (`%f`).

#### Perform Calculation on Each Numeric Variable

Once data is in a table, you can perform calculations on different table variables. One way is to use dot notation to refer to table variables by name and perform calculations. For example, calculate the total number of customers affected by power outages using the `sum` function, omitting any `NaN` values that might be in `T.Customers`.

```
totalCustomers = sum(T.Customers,'omitnan')
```

totalCustomers = 1.903e+08

You also can apply a function to every table variable, using the `varfun` function. `varfun` is particularly useful for applying a function and returning the results in another table.

However, you might want to apply a function only to variables of a particular type. You can specify the type of variable with the `vartype` function. Here I'm going to subscript into `T` for the numeric variables and calculate the mean of each one. And since the variables have some `NaN` values, I'm going to wrap `mean` in an anonymous function so I can use the `'omitnan'` flag.

T2 = T(:,vartype('numeric')); omean = @(x) mean(x,'omitnan'); meanT = varfun(omean,T2)

meanT = 1×2 table Fun_Loss Fun_Customers ________ _____________ 563.89 1.6693e+05

#### Perform Calculation on Groups in Numeric Variables

A more interesting view of the table is to group the data, and start looking for differences between the groups. For example, what is the difference in the mean power loss between the Northeast and Southwest regions?

To answer this question, you can start by specifying one or more table variables as *grouping variables*. The grouping variables define groups into which you split the other table variables. Then you can apply a function to each group within each table variable and the results. For more on grouping variables, see Grouping Variables to Split Data.

You can use grouping variables with the `varfun` function I described above. Specify `Region` as the grouping variable in this table. It's a categorical variable, making it especially convenient to use as a grouping variable. Specify `Loss` and `Customers` as the input variables, and calculate the mean values by region for these two variables. I'm going to use the same `omean` function I specified above.

meanByRegion = varfun(omean,T,'GroupingVariables','Region',... 'InputVariables',{'Loss','Customers'})

meanByRegion = 5×4 table Region GroupCount Fun_Loss Fun_Customers _________ __________ ________ _____________ MidWest 142 1137.7 2.4015e+05 NorthEast 557 551.65 1.4917e+05 SouthEast 389 495.35 1.6776e+05 SouthWest 26 493.88 2.6975e+05 West 354 433.37 1.5201e+05

Another way to apply a grouping variable to the data in a table variable is to use the `accumarray` function. If I convert `T.Region` to a numeric array, and extract `T.Loss` from `T`, then I can calculate mean power loss per region using `accumarray`, just as I did with `varfun`.

regions = double(T.Region); A = accumarray(regions,T.Loss,[],omean)

A = 1137.7 551.65 495.35 493.88 433.37

`accumarray` operates on arrays. So to use `accumarray` on a table variable, you must extract it from the table. Also, the grouping variable must be numeric, and the output argument is an array, not a table. While you can use `accumarray` on table variables, it lacks many of the conveniences that `varfun` provides.

You can specify more than one grouping variable using `varfun`. For example, I'll specify `Region` and `Cause` as grouping variables. The groups are defined as combinations of regions and causes.

meanByRegionAndCause = varfun(omean,T,'GroupingVariables',{'Region','Cause'},... 'InputVariables',{'Loss','Customers'}); meanByRegionAndCause(1:5,:)

ans = 5×5 table Region Cause GroupCount Fun_Loss Fun_Customers _______ ________________ __________ ________ _____________ MidWest attack 12 0 0 MidWest energy emergency 19 536.09 57603 MidWest equipment fault 9 343.37 29704 MidWest severe storm 31 1055.7 4.3584e+05 MidWest thunder storm 32 941.07 1.3301e+05

#### Multiple Variables as Input Arguments to Function

Another simple calculation is the mean duration of the power outages by region. The basis of this calculation is the difference between the `OutageTime` and `RestorationTime` table variables.

You might think to use `varfun` for this calculation too. The difficulty is that `varfun` applies a function to each table variable separately. But this calculation requires both variables. In other words, we want to apply a function that requires two input arguments.

The solution is to use the `rowfun` function. With `rowfun`, all the table variables are taken as input arguments. If the table has `N` variables, then the function you apply must accept `N` input arguments.

To perform this calculation, I'll start by defining an anonymous function that subtracts one input argument from the other, and then calculates the mean. Then I will calculate the mean duration of power outages by region using `rowfun`.

meanDiff = @(a,b) mean(abs(a-b),'omitnan'); meanOutageTimes = rowfun(meanDiff,T,'GroupingVariables','Region',... 'InputVariables',{'OutageTime','RestorationTime'})

meanOutageTimes = 5×3 table Region GroupCount Var3 _________ __________ _________ MidWest 142 819:14:44 NorthEast 557 581:02:18 SouthEast 389 40:49:49 SouthWest 26 59:31:07 West 354 673:27:12

Note that `OutageTime` and `RestorationTime` are datetime variables. You can perform arithmetic with datetime variables, just as you can with numeric variables.

To rename a variable, you can access the `VariableNames` property of the table and change its name there. Tables contain metadata, such as variable names and descriptions, in a property called `Properties`.

meanOutageTimes.Properties.VariableNames{'Var3'} = 'mean_OutageTime'; meanOutageTimes(1:5,:)

ans = 5×3 table Region GroupCount mean_OutageTime _________ __________ _______________ MidWest 142 819:14:44 NorthEast 557 581:02:18 SouthEast 389 40:49:49 SouthWest 26 59:31:07 West 354 673:27:12

#### Use Groups in Multiple Calculations and Tabulate Results

`varfun` and `rowfun` are suitable when you want to perform the same calculation with the table variables. But what if you want to calculate different quantities? For example, you might want to calculate the mean power loss, but also the minimum duration of power outages, by region. In that case, you can perform the calculations and tabulate the results using the `findgroups` and `splitapply` functions.

These functions work a little differently from `varfun` and `rowfun`. The `findgroups` function returns numeric indices that correspond to the grouping variables you specify. As a second output, it also returns a table of the groups. Then you can call `splitapply` to apply a function to each group within the variables.

For example, I'll calculate the mean power loss, the minimum outage time, and the maximum number of customers affected, by region. I will specify the groups once using `findgroups`. Then I can use the groups in multiple calls to `splitapply`.

I'm also going to switch gears a little bit, by removing all rows with `NaN` or missing values. I'll use the `rmmissing` function to remove these rows, so that I don't have to specify the `'omitnan'` flag in every function call.

```
T = rmmissing(T);
[G,results] = findgroups(T(:,'Region'));
meanLoss = splitapply(@mean,T.Loss,G);
minOutageTime = splitapply(@min,T.RestorationTime - T.OutageTime,G);
maxCustomers = splitapply(@max,T.Customers,G)
```

maxCustomers = 3.295e+06 5.9689e+06 2.2249e+06 1.8202e+06 4.26e+06

The output of `splitapply` is an array. `maxCustomers` is a 5-by-1 numeric array. However, you can tabulate the results by adding them as variables to the table `results`, the second output from `findgroups`.

results.meanLoss = meanLoss; results.minOutageTime = minOutageTime; results.maxCustomers = maxCustomers

results = 5×4 table Region meanLoss minOutageTime maxCustomers _________ ________ _____________ ____________ MidWest 907.19 00:00:00 3.295e+06 NorthEast 383.86 00:00:00 5.9689e+06 SouthEast 508.34 00:00:00 2.2249e+06 SouthWest 541.66 00:28:00 1.8202e+06 West 429.73 00:00:00 4.26e+06

#### Perform Calculations on Tall Table

So far, I've worked with a table that is small enough to fit into memory. But what if there is so much data that it won't all fit into memory? I might still want to treat it as a table and use the same functions.

That can easily be done by creating a *tall table*. A tall table is a kind of a tall array in MATLAB. Tall arrays and tall tables know how to read the data in one chunk at a time, perform the calculations you want, and then gather up the output at the end. The syntax for working with a tall table is very similar to that for working with a table.

For more information on tall arrays and tall tables, see Tall Arrays.

To show how this works, I'll create a tall table out of `outages.csv`. Of course it's a bit silly to create a tall table out of a file that fits in memory, but this illustrates how to work with a much larger table.

Instead of calling `readtable`, I'll start by calling `datastore` to read `outages.csv` into a datastore.

Then I'll call `tall` on `ds`, to create a tall table out of the datastore. Now I have a tall table that looks and acts very much like the table I worked with in the previous sections. One difference you see is that the tall table is displayed as an M-by-6 table, showing that the number of rows is not yet known.

```
ds = datastore('outages.csv');
T = tall(ds)
```

Starting parallel pool (parpool) using the 'local' profile ... connected to 2 workers. T = M×6 tall table Region OutageTime Loss Customers RestorationTime Cause ___________ ________________ ______ __________ ________________ _________________ 'SouthWest' 2002-02-01 12:18 458.98 1.8202e+06 2002-02-07 16:50 'winter storm' 'SouthEast' 2003-01-23 00:49 530.14 2.1204e+05 NaT 'winter storm' 'SouthEast' 2003-02-07 21:15 289.4 1.4294e+05 2003-02-17 08:14 'winter storm' 'West' 2004-04-06 05:44 434.81 3.4037e+05 2004-04-06 06:10 'equipment fault' 'MidWest' 2002-03-16 06:18 186.44 2.1275e+05 2002-03-18 23:23 'severe storm' 'West' 2003-06-18 02:49 0 0 2003-06-18 10:54 'attack' 'West' 2004-06-20 14:39 231.29 NaN 2004-06-20 19:16 'equipment fault' 'West' 2002-06-06 19:28 311.86 NaN 2002-06-07 00:51 'equipment fault' : : : : : : : : : : : :

Now I can use `findgroups` and `splitapply` to perform some of the same calculations as before. Again I will wrap `mean` in an anonymous function so I can ignore `NaN` values, as I did above.

```
omean = @(x) mean(x,'omitnan');
T.Region = categorical(T.Region);
T.Cause = categorical(T.Cause);
G = findgroups(T.Region);
meanLoss = splitapply(omean,T.Loss,G);
meanCustomers = splitapply(omean,T.Customers,G)
```

meanCustomers = M×1 tall double column vector ? ? ? : :

Instead of seeing the output, we see a trail of question marks. What does this mean? Simply that I have not performed any calculations yet. At this point, I have only defined the calculations I want to perform on the tall table. No calculations are performed until I *gather* the results, by calling the `gather` function. The output of `gather` is not a tall array and must fit into memory.

meanLoss = gather(meanLoss); meanCustomers = gather(meanCustomers)

Evaluating tall expression using the Parallel Pool 'local': - Pass 1 of 4: Completed in 4 sec - Pass 2 of 4: Completed in 2 sec - Pass 3 of 4: Completed in 2 sec - Pass 4 of 4: Completed in 2 sec Evaluation completed in 25 sec Evaluating tall expression using the Parallel Pool 'local': - Pass 1 of 1: Completed in 2 sec Evaluation completed in 5 sec meanCustomers = 2.4015e+05 1.4917e+05 1.6776e+05 2.6975e+05 1.5201e+05

Now let's tabulate the results in a table. Since `meanLoss` and `meanCustomers` are not tall arrays, `results` is not a tall table. Add the regions as another table variable.

results = table(meanLoss,meanCustomers) region = unique(T.Region); results.region = gather(region)

results = 5×2 table meanLoss meanCustomers ________ _____________ 1137.7 2.4015e+05 551.65 1.4917e+05 495.35 1.6776e+05 493.88 2.6975e+05 433.37 1.5201e+05 Evaluating tall expression using the Parallel Pool 'local': - Pass 1 of 1: Completed in 1 sec Evaluation completed in 2 sec results = 5×3 table meanLoss meanCustomers region ________ _____________ _________ 1137.7 2.4015e+05 MidWest 551.65 1.4917e+05 NorthEast 495.35 1.6776e+05 SouthEast 493.88 2.6975e+05 SouthWest 433.37 1.5201e+05 West

#### Turning the Tables on You

Here I have shown you several ways you can group data in tables for calculations. To summarize, you can use one or more grouping variables to specify groups within the other table variables. Then you can apply functions to the groups in the table variables.

To apply:

- A function to a single table variable and return an array, use
`accumarray`. - The same function to each table variable and return a table, use
`varfun`. - A function that requires all the table variables as input arguments and return a table, use
`rowfun`. - Different functions to different table variables and build a table of results, use
`findgroups`and`splitapply`.

How about you? Have done analysis with tables where `accumarray`, `varfun`, `rowfun`, `findgroups` and `splitapply` might have helped? Do you have cases where you need tall tables? Let us know here.

Get the MATLAB code

Published with MATLAB® R2017a

**Category:**- Data types,
- Statistics

### Note

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## 4 CommentsOldest to Newest

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**output**arguments that the min function can return. However, you cannot instruct varfun to return multiple output arguments from the applied function. So one way to approach this problem is to call varfun twice. The first time, call it using min, to get the minima of the table variables. The second time, call it using a function that find the locations of the minima. In all likelihood, you would need to write a function of your own that gets the second output from min, and just returns that. The result is two tables that you can horizontally concatenate, if you want the minima and locations in one table. An alternative approach might be to try the rowfun function, which can return multiple outputs from the applied function. In that case, you would write FindMin as a function that accepts N inputs (as you have N table variables), and that returns 2*N outputs (the minimum for each variable, and its location). A final note of caution: if you group the table variables, you will get misleading results from either approach. The reason is that if you group the variables, then you will find minima and their locations within the groups, not within the table as a whole. If you wish to index back into the table using locations, then the locations within groups are of no use. Keep this information in mind if you later decide that you need to group your data. I hope my comments give you some helpful guidance. Please contact MathWorks if you find you need further assistance. Best Regards, Stephen Doe

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