Today’s challenge is one where you need to figure out if two rectangles have a non-zero area of overlap.
The rectangles will be specified as follows:

Just fill in your part of the code until… 더 읽어보기 >>

9:42

This week we will be looking at the MATLAB class system. This video does not cover the “why” of doing OOP (Object Oriented Programming) in MATLAB. It just covers a very simple example… 더 읽어보기 >>

This is a puzzler without explanation. Brett got it in about five minutes, some of the other folks wandering near my office got it in just under 20.
The data to explore.
Remember to use the… 더 읽어보기 >>

3:17

This short video shows how you can take a sparsely sampled sine wave and use interp1 to interpolate the missing data points. Different interpolations such as linear, spline and nearest are all shown…. 더 읽어보기 >>

Update: This solution was found faster than expected. I have replaced the original with a stronger solution that I was holding in reserve. Congrats to DanK for solving the original ( found here… 더 읽어보기 >>

3:05

Sometimes in MATLAB you are going to want to store different data types together in one construct rather than try and keep track of different variables. Structures work for this, but sometimes it is… 더 읽어보기 >>

I wanted to thank everyone for posting their videos as requested in my prior post [click here]. Here are some of my favorite entries. I will be in touch with the authors to send them some fabulous… 더 읽어보기 >>

3:17

This week’s puzzler is significantly harder than others we have done in the past, I would be surprised (and delighted) to see an answer before I go home tonight… The challenge is shown… 더 읽어보기 >>

It is no secret that I like teaching MATLAB through videos. I use Camtasia to make and edit my videos, I am very happy using it. If you want to make MATLAB videos too, you can use Jing, by the… 더 읽어보기 >>

0:57

Here is a new MATLAB Puzzler. Given two vectors representing the X and Y coordinates of some points, find the two closest points in Cartesian space. n = 10; x = rand(1,n); y = rand(1,n); … 더 읽어보기 >>